回文数
Topic sourcedef is_pailndrome(n): n = str(n) if(len(n) == 2): return n[0] == n[1] left = n[:int(len(n)/2)] right = n[int(len(n)/2) + 1:][::-1] return left == right
output = list(filter(is_pailndrome, range(1, 1000)))
print(output)
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def is_pailndrome(n): n = str(n) if(len(n) == 2): return n[0] == n[1] left = n[:int(len(n)/2)] right = n[int(len(n)/2) + 1:][::-1] return left == right
output = list(filter(is_pailndrome, range(1, 1000)))
print(output)
我就不信还有人起这昵称
def is_pailndrome(n): n = str(n) left = n[:int(len(n)/2)] right = n[int(len(n)/2) + 1:][::-1] return left == right
output = list(filter(is_pailndrome, range(1, 1000)))
print(output)