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回文数

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def is_pailndrome(n): n = str(n) left = n[:int(len(n)/2)] right = n[int(len(n)/2) + 1:][::-1] return left == right

output = list(filter(is_pailndrome, range(1, 1000)))

print(output)

def is_pailndrome(n): n = str(n) if(len(n) == 2): return n[0] == n[1] left = n[:int(len(n)/2)] right = n[int(len(n)/2) + 1:][::-1] return left == right

output = list(filter(is_pailndrome, range(1, 1000)))

print(output)


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