输出结果后面怎么有空格

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#1 Created at ... [Delete] [Delete and Lock User]

print(L[0][0],'\n',L[1][1],'\n',L[-1][-1])

输出结果为： Apple Python Lisa 怎么去掉后面两行的空格

#2 Created at ... [Delete] [Delete and Lock User]

print(L[0][0], L[1][1], L[-1][-1], sep='\n')

#3 Created at ... [Delete] [Delete and Lock User]

这个sep='\n'是什么意思啊

#4 Created at ... [Delete] [Delete and Lock User]

separation 分开; separated 分开的我猜，sep='\n'意思是以换行分隔，或者意思是，逗号变成换行。

我猜的 ——一只小白

#5 Created at ... [Delete] [Delete and Lock User]

用 print('''

''') 这个可以吗，没试过

#6 Created at ... [Delete] [Delete and Lock User]

最后打印出来的是L[0][0]L[1][1]L[2][2]，并不指向list的索引元素，可能这个方法把数组当作普通的字符串来表达了

#7 Created at ... [Delete] [Delete and Lock User]

sep是print函数内的一个参数，作用是实现分隔符，sep='\n'代表那三个元素之间用\n分隔，如果换成sep=','就是用逗号分隔

#8 Created at ... [Delete] [Delete and Lock User]

print(L[0][0]+'\n'+L[1][1]+'\n'+L[2][2])